Hi, > So I would suggest forming proper grids if you can. I agree with David. > isis> c.bin_lo = [1,2,3,4,5]; > isis> c.bin_hi = [c.bin_lo[[1:]], c.bin_lo[-1]+1] ; To do this, John provides also the make_hi_grid function: isis> c.bin_hi = make_hi_grid(c.bin_lo); Cheers, Manfred make_hi_grid SYNOPSIS Use a single grid array to define a histogram grid USAGE hi[] = make_hi_grid (lo[]); DESCRIPTION Given a grid which provides the lower bin edges of a histogram grid, the high edges are defined as hi[[i:n-1]] = [ lo[[1:n-1]], 2*lo[n-1] - lo[n-2] ]; so that the last two bins have the same width. -- Manfred Hanke Manfred.Hanke(at)sternwarte.uni-erlangen.de Dr. Karl Remeis-Sternwarte, Universität Erlangen-Nürnberg Sternwartstraße 7, 96049 Bamberg Tel. (0951) 95222-34 Fax (0951) 95222-22 www: http://pulsar.sternwarte.uni-erlangen.de/hanke -- ---- You received this message because you are subscribed to the isis-users list. To unsubscribe, send a message to isis-users-request_at_email.domain.hiddenwith the first line of the message as: unsubscribeReceived on Fri Nov 30 2007 - 05:51:49 EST
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